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Rob Rule

Rusten Crating

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3rd July, 2010 at 04:28:12 -

Okay, so. One hundred prisoners are to be transferred to a special new prison. In this new prison they are kept in individual rooms, allowed no contact with each other. There is a Room 101, containing only a light bulb and a switch which operates it. The switch begins in the 'off' position. Randomly, one prisoner is chosen and led to Room 101, where they may change the position of the switch if they wish, or leave it as it is. This process is repeated until a prisoner correctly states "everyone has visited this room now", at which point they are all released. If anyone says this without it being true then they are all executed.

The prisoners have one night, before being transferred, to work out a strategy that will ensure their eventual release. What can they do?

 
It'll all blow over.

-MacAdaM-

Megaman Fosho

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3rd July, 2010 at 04:54:36 -

Kill all prisoners but one.

 
Your just jealous that you're not as awesome as me.
(And my megaman avatar )

MBK



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5th July, 2010 at 21:14:07 -

Does each prisoner get only one visit to the room? ... or can they be chosen to go to the room more than once each?


 
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OMC

What a goofball

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KlikCast Musician! Guy with a HatSomewhat CrazyARGH SignLikes TDCHas Donated, Thank You!Retired Admin
5th July, 2010 at 21:22:13 -

You and your tricksy logic puzzles.

If they're in the room and have not turned the light off and the light is on, they turn the light off. If it's on and they've turned it off before, they leave it alone. Only one designated person turns the light back on when it's off. Assuming they can go repeatedly and indefinitely, the designated person just has to turn the light on 99 times.

But I suppose since it starts in the off position, it would be better to reverse the on and off in that solution.

This puzzle seems very familiar. I may very well have heard it in the past. Or I'm just a genius.

No wait, I was thinking of the three bulbs and a staircase thing.

Edited by OMC

 

  		
  		

MBK



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5th July, 2010 at 21:46:53 -

If there was no plan, and they wanted us to fiddle with the light switch and guess ... and the guards wait outside the room while you do it ... I'd take the bulb out of the socket, break it, and use it to cut the guards throat, then release the other prisoners with his key.



 
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Rob Rule

Rusten Crating

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5th July, 2010 at 21:55:38 -

OMC nails, but yes. of course it's reversed. Huzzah!

 
It'll all blow over.

MBK



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13th July, 2010 at 23:40:42 -

Congrats OMC!
I didn't figure this one out, but I finally figured out the real answer to the probability riddle.

The answer is to give a valid explanation that loops logically. You must find a way to leave the loop with a logical explanation and return to the beginning. It's like in programming how if you're running a loop that never ends, it'll crash the program unless you provide a way out of the loop that logically works. But once you do provide that logical means of escape, the program runs fine.


 
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Joellie



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19th July, 2010 at 21:34:07 -

Omg this litterally had me clueless i was thinking along the lines of "kill the guards and run" theory!

 
n/a

Rob Rule

Rusten Crating

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3rd August, 2010 at 21:31:56 -


Originally Posted by MBK
Congrats OMC!
I didn't figure this one out, but I finally figured out the real answer to the probability riddle.

The answer is to give a valid explanation that loops logically. You must find a way to leave the loop with a logical explanation and return to the beginning. It's like in programming how if you're running a loop that never ends, it'll crash the program unless you provide a way out of the loop that logically works. But once you do provide that logical means of escape, the program runs fine.



The probability riddle was a classic paradox. A paradox, man.

 
It'll all blow over.

Lazernaut



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4th August, 2010 at 07:20:50 -


Originally Posted by Joellie
Omg this litterally had me clueless i was thinking along the lines of "kill the guards and run" theory!



I'm either not smart enough, or too lazy, to think such things through. The above would be my solution too

 
n/a

Knockturnal

Nothing to see here turn back

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8th August, 2010 at 17:26:07 -

All right, smart guys:

Three gods A, B, and C are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language, in which the words for yes and no are 'da' and 'ja', in some order. You do not know which word means which.

 
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OMC

What a goofball

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KlikCast Musician! Guy with a HatSomewhat CrazyARGH SignLikes TDCHas Donated, Thank You!Retired Admin
8th August, 2010 at 17:40:33 -

Rob already asked that one here: http://create-games.com/forum_post.asp?id=272832&s=15

 

  		
  		

Knockturnal

Nothing to see here turn back

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8th August, 2010 at 18:13:31 -



'S my favorite...

 
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ivanchotopalov



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  10/03/2010
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11th August, 2010 at 06:40:21 -

Kill the guards and run sounds about right

 
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