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Jon C-B
I create vaporware
Registered
23/04/2008
Points
237
    
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4th August, 2009 at 18:45:14 -
How would you make it so that an enemy has a 1 out of 5 chance of dropping an item?
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Del Duio
Born in a Bowling Alley
Registered
29/07/2005
Points
1078
       
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4th August, 2009 at 18:59:21 -
Well what I'm doing now is to always have a counter set a random # from 1 to 100.
Then, when the enemy is killed, there's a condition after it like this:
If "enemyHP" < 0
+ "RandomNum" is >= 80
+ Enemy animation "disappearing" is NOT playing
+ run event once per loop (or whatever it is)
-->
Create the item at a position on the enemy and destroy the enemy.
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This is pretty simple but you can have other events like this afterwards to give an enemy different chances to drop different items. I used 100 so that I could say an enemy had a 14% chance to drop a potion for example.
Hope this helps!
--
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Jon C-B
I create vaporware
Registered
23/04/2008
Points
237
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4th August, 2009 at 19:25:16 -
That works great thanks!
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GamesterXIII
Registered
04/12/2008
Points
1110
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5th August, 2009 at 04:41:18 -
The way Del Duio said it will work, but it only goes to 99 (not that big of a deal, but if you're nitpicky like me, it is).
Any time you deal with random numbers in which you want to be 1-x (ex 1-100), always do this.
Set X to random(100)+1 instead of set X to random(100)
IF you set a value to random(100) it sets the number to 0, 99, or any numbers between those two so adding one would mean it picks 1,100, or any number between.
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