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Posted By
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Message
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siven
I EAT ROCKS
Registered
03/11/2008
Points
604
 
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4th January, 2011 at 21:10:11 -
So for example lets say i have an object that has none of the default animations used, so all 12 of them are blank. lets say i have 4 more animations after that, lets call them animation A, B, C, and D.
from what i understand from looking at other peoples coding, in order to skip those first empty frames you have to put set animation to Random(12)+4 (12 being the first animations, and 4 being the last 4 you actually want to display)
am i correct? or does the first animation count as animation 0? therefor making the coding Random(11)+4?
or am i completely misunderstanding these lines of coding?
[Game design makes my brain feel like its gonna explode.]
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OMC
What a goofball
Registered
21/05/2007
Points
3516
      
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4th January, 2011 at 21:25:32 -
Random(4)+13 should do it.
Random() generates a number between 0 and the number you enter (including 0). So the possibilities for Random(4) are 0, 1, 2, and 3. If you add 13 to each of these, the possibilities are 13, 14, 15, and 16.
That should do it... Seems complicated, but at least you're not dealing with a system that always generates a decimal number between 0 and 1 no matter what!
 Edited by OMC
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siven
I EAT ROCKS
Registered
03/11/2008
Points
604
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4th January, 2011 at 21:32:33 -
oooooooooooh! that makes plenty of sense! thank you sir, i think you may have just aided me in fixing a glitch ive been trying to fix for about a week strait. Its been driving me crazy lol.
[Game design makes my brain feel like its gonna explode.]
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Mark McCauley
Registered
18/02/2009
Points
291
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5th January, 2011 at 10:25:50 -
be a good idea to do
set value to 13+random(4)
rather than random(4)+13
because (I think ) the computer will treat the latter as random(17)
http://www.reddwarf.co.uk/forum/messages.cfm?threadid=44227736-C46F-AC56-02EBA05285818C14
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Jon Lambert
Administrator
Vaporware Master
Registered
19/12/2004
Points
8235
    
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5th January, 2011 at 13:31:08 -
Originally Posted by Mark McCauley
be a good idea to do
set value to 13+random(4)
rather than random(4)+13
because (I think ) the computer will treat the latter as random(17)
No, it won't, because the +13 is outside of the parentheses.
Sandwich Time!Whoo!
JoyCheck & KeyCheck Widgets
For easy implementation of customizable joystick and keyboard controls.
http://www.create-games.com/download.asp?id=8364
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Hagar
Administrator
Old klik fart
Registered
20/02/2002
Points
1692
 
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5th January, 2011 at 14:06:48 -
A+B = B+A 
n/a
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Mark McCauley
Registered
18/02/2009
Points
291
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6th January, 2011 at 12:20:07 -
OBVIOUSLY, it is outside the brackets ,
but I could've sworn the computer has treated the number as a whole before , maybe its just my schizophrenic pc.anyone ever have this happen to them?
but thanks for the correction.
http://www.reddwarf.co.uk/forum/messages.cfm?threadid=44227736-C46F-AC56-02EBA05285818C14
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